Originally Posted by Wobin
#table only works for consecutively assigned numerical indexes, so t = {"a", "b", "c"} or t={[1] = "a", [2] = "b", [3] = "c"}
As you're using itemIds as the index, you're ending up with nonconsecutive elements. Use pairs(t) to iterate through and count elements
Code:
local count = 0
for k in pairs(t) do count = count + 1 end
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Hmm ok I see. Will have to create my own count() func then
Will try this and see how it works. Thanks !